objdump, displaying without offsets
objdump, displaying without offsets When dumping an executable file I want only code segment be printed standart output. Not offsets and binary form of codes.I can note achive it from man objdump.Is there a way? 2 Answers 2 You can suppress the object code hex dump with --no-show-raw-insn If you have jumps in the code then you need the offsets to make sense of them, but if you really want to strip them, filter the code with something like: objdump -d --no-show-raw-insn myfile.o | perl -p -e 's/^s+(S+):t//;' Example output: 0000000000000000 <foo>: retq lea 0x0(%rsi),%rsi lea 0x0(%rdi),%rdi Disassembly of section .gnu.linkonce.t.goo: 0000000000000000 <goo>: retq lea 0x0(%rsi),%rsi lea 0x0(%rdi),%rdi If you want to achieve same output as Peeter Joot showed but without using Perl command line. Then you can use Grep and Cut tool instead, like shown below. objdump -d --...