Xcode/Swift: How to add extra argument to a bash execution

I have this Code:

func syncShellExec(path: String?) {
let script = [path!]
let process = Process()
let outputPipe = Pipe()
let filelHandler = outputPipe.fileHandleForReading

process.launchPath = "/bin/bash"
process.arguments = script
process.standardOutput = outputPipe
.
.
.


In Swift I call it this way:

self.syncShellExec(path: Bundle.main.path(forResource: "initial", ofType: "command"))


Now I want to add an Extra argument for the script itself (using Functions within the Bashscript). In Terminal it would be like this:

/usr/bin/bash initial.command Do_My_Function


How to add this to the process?

1 Answer
1

You can add a “variadic parameter” to your Swift function,
and append the arguments to process.arguments:

process.arguments

func syncShellExec(path: String, args: String...) {

let process = Process()
process.launchPath = "/bin/bash"
process.arguments = [path] + args

// ...
}


Now you can call for example:

let scriptPath = Bundle.main.path(forResource: "initial", ofType: "command")!

syncShellExec(path: scriptPath)
syncShellExec(path: scriptPath, args: "Do_My_Function")
syncShellExec(path: scriptPath, args: "arg1", "arg2")


Remark: The syncShellExec() function expects a path to a script,
therefore I would not make that parameter optional and force-unwrap
it inside the function. On the other hand, Bundle.main.path(...)
would only return nil if the resource is missing. That is a
programming error so that force-unwrapping the return value is
justified.

syncShellExec()

Bundle.main.path(...)

If the number of arguments is only determined at runtime then
you can define the arguments as an array

func syncShellExec(path: String, args: [String] = )


and call it as

syncShellExec(path: scriptPath)
syncShellExec(path: scriptPath, args: ["Do_My_Function"])
syncShellExec(path: scriptPath, args: ["arg1", "arg2"])


!

Bundle.main.path(forResource: "initial", ofType: "command")!

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