JS: Forward to a site with random parts in the URL

by opening a HTML-site, I want to redirect to the following page:

www.xyz.de?user=default&f1=OPTION1&f2=OPTION2&f3=OPTION3&f4=OPTION4&f5=OPTION5&... etc.

The value for the "OPTIONS" should be randomly selected from a list (array) for every OPTION (1,2,3,4,5,..).

How can I do this with Javascript?

kind regards

1 Answer
1

Hopefully this will help you, you didn't provide much details or a demo code, so this is from my point of understanding only.

<p id="Link">Link Here</p>
<p id="randoms">Randomly Sortde Array</p>
<script>
var options = ["OPTION1", "OPTION2", "OPTION3", "OPTION4", "OPTION5"]; // Our main array of options
options.sort(function(a, b){return 0.5 - Math.random()}); // We reorder the elements randomly, using : function(a, b){return 1 - Math.random()} will give us the reversed array.
document.getElementById("randoms").innerHTML = options; // Our "randmoly" sorted array
document.getElementById("Link").innerHTML = "www.xyz.de/?user=default&f1="+options[0]+"&f2="+options[1]+"&f3="+options[2]+"&f4="+options[3]+"&f5="+options[4]; // Our Final Link
</script>


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