Extract IPs from multiples websites using bash and awk

I'm looking for the best way to get multiples websites IPs and output them as "domain.com:","1.1.1.1" in order to achieve this I was thinking on using nslookup (not sure if is the best option but I don't want to use ping)

"domain.com:","1.1.1.1"

nslookup

Well I was trying something like:

for domain in $(cat domains.txt)
do
nslookup $domain 8.8.8.8 | awk '/Address: ([[:digit:]]+.){3}/{gsub(/.$/,"",$1); printf ""%s","%s"n",$1,$NF}'; done


With this, I'm get this output:

"Address:","64.233.190.101"
"Address:","64.233.190.138"
"Address:","64.233.190.100"
"Address:","64.233.190.139"
"Address:","64.233.190.113"
"Address:","64.233.190.102"
"Address:","98.137.246.8"
"Address:","98.138.219.231"
"Address:","72.30.35.9"
"Address:","72.30.35.10"
"Address:","98.138.219.232"
"Address:","98.137.246.7"
"Address:","93.184.216.34"


Expected Output

"google.com","64.233.190.101"
"google.com","64.233.190.138"
"google.com","64.233.190.100"
"google.com","64.233.190.139"
"google.com","64.233.190.113"
"google.com","64.233.190.102"
"yahoo.com","98.137.246.8"
"yahoo.com","98.138.219.231"
"yahoo.com","72.30.35.9"
"yahoo.com","72.30.35.10"
"yahoo.com","98.138.219.232"
"yahoo.com","98.137.246.7"
"example.com","93.184.216.34"


domains.txt content:

google.com
yahoo.com
example.com


I was trying to do this but I can’t get the correct domain under "domain.com", on the output.

"domain.com",

I'm not sure if using $domain or awk, Can any one help me to get the correct syntax. Please note that I need requested domain inside "domain.com", not the Name: in nslookup

"domain.com",

Name:

Thanks.

1 Answer
1

domain="mail.yahoo.com"
nslookup "$domain" 8.8.8.8 | awk -v n="$domain" -F ' +' '$1=="Address:"{print """n"",""$2"""}'


Output:

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