swift: working with string

We have a simple string:

let str = ""abc", "def","ghi" , 123.4, 567, "qwe,rty""


If we do this:

let parsedCSV = str
.components(separatedBy: .newlines)
.filter { !$0.isEmpty }
.map { $0.components(separatedBy: ",") }
.map { $0.map { $0.trimmingCharacters(in: .whitespaces) } }
print(parsedCSV)


we get this:

[[""abc"", ""def"", ""ghi"", "123.4", "567", ""qwe", "rty""]]


Is there a simple solution (using functional programming) not to split the last element "qwe,rty", because we know that it's one whole thing?

"qwe,rty"

"

3 Answers
3

Well this is a hack, it works for this case.... not very simple solution for complex issue ...

let str = ""abc", "def","ghi" , 123.4, 567, "qwe,rty""

let parsedCSV = str
.components(separatedBy: .newlines)
.filter { !$0.isEmpty }
.map { $0.components(separatedBy: ",") }
.map { $0.map { $0.trimmingCharacters(in: .whitespaces) } }.reduce() { (result, items) -> [String] in
var goodItems = items.filter{ $0.components(separatedBy: """).count == 3 || $0.components(separatedBy: """).count == 1}
let arr = items.filter{ $0.components(separatedBy: """).count == 2}
var join:[String] =
for x in 0..<arr.count {
let j = x + 1
if j < arr.count {
join = [arr[x] + "," + arr[j]]
}
}
goodItems.append(contentsOf: join)
return goodItems
}


print(parsedCSV)


print out

[""abc"", ""def"", ""ghi"", "123.4", "567", ""qwe,rty""]

I've done that.

let str = "_, * ,, "abc", 000, def, ghi , 123.4,, 567, "qwe,rty,eur", jkl"
let separator = ","
let parsedCSV = str
.components(separatedBy: .newlines)
.filter { !$0.isEmpty }
.map { $0.components(separatedBy: separator).map { $0.trimmingCharacters(in: .whitespaces) } }
.reduce() { (result, items) -> [String] in
var result: [String] =
for item in items {
guard let last = result.last, last.components(separatedBy: """).count % 2 == 0 else {
result.append(item)
continue
}
result.removeLast()
let lastModified = record + separator + item
result.append(lastModified)

}
return result
}.map { $0.trimmingCharacters(in: CharacterSet(charactersIn: """)) }
print(parsedCSV)


["_", "*", "", "abc", "000", "def", "ghi", "123.4", "", "567",
"qwe,rty,eur", "jkl"]

If you do not mind using Regular Expression, you can write something like this:

let str = "_, * ,, "abc", 000, def, ghi , 123.4,, 567, "qwe,rty,eur", jkl"

let pattern = "((?:[^",]|"[^"]*")*)(?:,|$)"
let regex = try! NSRegularExpression(pattern: pattern)

let parsedCSV = regex.matches(in: str, options: .anchored, range: NSRange(0..<str.utf16.count))
.map {$0.range(at: 1)}
.filter {$0.location != NSNotFound && $0.location < str.utf16.count}
.map {String(str[Range<String.Index>($0, in: str)!]).trimmingCharacters(in: .whitespaces)}
.map {$0.trimmingCharacters(in: CharacterSet(charactersIn: """))}
print(parsedCSV) //->["_", "*", "", "abc", "000", "def", "ghi", "123.4", "", "567", "qwe,rty,eur", "jkl"]


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